Base | Representation |
---|---|
bin | 11010101101110110… |
… | …11001101110011111 |
3 | 1101000121110212022021 |
4 | 31112323121232133 |
5 | 213333342024320 |
6 | 10331135001011 |
7 | 1015304105650 |
oct | 152673315637 |
9 | 41017425267 |
10 | 14343314335 |
11 | 60a0477399 |
12 | 2943669167 |
13 | 1477793c5c |
14 | 9a0d23527 |
15 | 58e34adaa |
hex | 356ed9b9f |
14343314335 has 16 divisors (see below), whose sum is σ = 20150609472. Its totient is φ = 9595526400.
The previous prime is 14343314327. The next prime is 14343314351. The reversal of 14343314335 is 53341334341.
It is not a de Polignac number, because 14343314335 - 23 = 14343314327 is a prime.
It is a super-2 number, since 2×143433143352 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14343314335.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4996236 + ... + 4999105.
It is an arithmetic number, because the mean of its divisors is an integer number (1259413092).
Almost surely, 214343314335 is an apocalyptic number.
14343314335 is a deficient number, since it is larger than the sum of its proper divisors (5807295137).
14343314335 is an equidigital number, since it uses as much as digits as its factorization.
14343314335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9995394.
The product of its digits is 77760, while the sum is 34.
Adding to 14343314335 its reverse (53341334341), we get a palindrome (67684648676).
The spelling of 14343314335 in words is "fourteen billion, three hundred forty-three million, three hundred fourteen thousand, three hundred thirty-five".
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