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1434343402417 is a prime number
BaseRepresentation
bin10100110111110101100…
…001110110101110110001
312002010021212011101212011
4110313311201312232301
5142000013402334132
63014532301002521
7205425236520502
oct24676541665661
95063255141764
101434343402417
115033355038a2
121b1b9a853441
13a5347aa6873
144d5cb838ba9
152749d242b47
hex14df5876bb1

1434343402417 has 2 divisors, whose sum is σ = 1434343402418. Its totient is φ = 1434343402416.

The previous prime is 1434343402369. The next prime is 1434343402439. The reversal of 1434343402417 is 7142043434341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 909818376336 + 524525026081 = 953844^2 + 724241^2 .

It is a cyclic number.

It is not a de Polignac number, because 1434343402417 - 223 = 1434335013809 is a prime.

It is a super-3 number, since 3×14343434024173 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1434343402417.

It is not a weakly prime, because it can be changed into another prime (1434343402477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717171701208 + 717171701209.

It is an arithmetic number, because the mean of its divisors is an integer number (717171701209).

Almost surely, 21434343402417 is an apocalyptic number.

It is an amenable number.

1434343402417 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434343402417 is an equidigital number, since it uses as much as digits as its factorization.

1434343402417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 387072, while the sum is 40.

Adding to 1434343402417 its reverse (7142043434341), we get a palindrome (8576386836758).

The spelling of 1434343402417 in words is "one trillion, four hundred thirty-four billion, three hundred forty-three million, four hundred two thousand, four hundred seventeen".