14344000045 has 4 divisors (see below), whose sum is σ = 17212800060. Its totient is φ = 11475200032.

The previous prime is 14344000037. The next prime is 14344000057. The reversal of 14344000045 is 54000044341.

14344000045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54000044341 = 1231 ⋅43866811.

It can be written as a sum of positive squares in 2 ways, for example, as 11060939241 + 3283060804 = 105171^2 + 57298^2 .

It is a cyclic number.

It is not a de Polignac number, because 14344000045 - 2³ = 14344000037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14343999983 and 14344000019.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1434400000 + ... + 1434400009.

It is an arithmetic number, because the mean of its divisors is an integer number (4303200015).

Almost surely, 2^14344000045 is an apocalyptic number.

It is an amenable number.

14344000045 is a deficient number, since it is larger than the sum of its proper divisors (2868800015).

14344000045 is an equidigital number, since it uses as much as digits as its factorization.

14344000045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2868800014.

The product of its (nonzero) digits is 3840, while the sum is 25.

Adding to 14344000045 its reverse (54000044341), we get a palindrome (68344044386).

The spelling of 14344000045 in words is "fourteen billion, three hundred forty-four million, forty-five", and thus it is an aban number.