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14344001311201 = 291992485531331
BaseRepresentation
bin1101000010111011100100…
…0110100101000111100001
31212210021101010002012002021
43100232321012211013201
53340003003313424301
650301313201021441
73010214503301152
oct320567106450741
955707333065067
1014344001311201
11463029087a291
121737b69024881
13800830ac5573
14378379353929
1519d1c14c78a1
hexd0bb91a51e1

14344001311201 has 8 divisors (see below), whose sum is σ = 14913187992000. Its totient is φ = 13779785693520.

The previous prime is 14344001311193. The next prime is 14344001311273. The reversal of 14344001311201 is 10211310044341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14344001311201 - 23 = 14344001311193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14344001311001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1242759895 + ... + 1242771436.

It is an arithmetic number, because the mean of its divisors is an integer number (1864148499000).

Almost surely, 214344001311201 is an apocalyptic number.

It is an amenable number.

14344001311201 is a deficient number, since it is larger than the sum of its proper divisors (569186680799).

14344001311201 is a wasteful number, since it uses less digits than its factorization.

14344001311201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2485531559.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14344001311201 its reverse (10211310044341), we get a palindrome (24555311355542).

The spelling of 14344001311201 in words is "fourteen trillion, three hundred forty-four billion, one million, three hundred eleven thousand, two hundred one".

Divisors: 1 29 199 5771 2485531331 72080408599 494620734869 14344001311201