Base | Representation |
---|---|
bin | 10100110111111000111… |
… | …110110100100011011001 |
3 | 12002010102220011021212222 |
4 | 110313320332310203121 |
5 | 142000123214433241 |
6 | 3014542130313425 |
7 | 205426542052664 |
oct | 24677076644331 |
9 | 5063386137788 |
10 | 1434401327321 |
11 | 503365177716 |
12 | 1b1bb6128875 |
13 | a5356aa8161 |
14 | 4d5d53d66db |
15 | 274a3385a4b |
hex | 14df8fb48d9 |
1434401327321 has 2 divisors, whose sum is σ = 1434401327322. Its totient is φ = 1434401327320.
The previous prime is 1434401327287. The next prime is 1434401327351. The reversal of 1434401327321 is 1237231044341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 742569975625 + 691831351696 = 861725^2 + 831764^2 .
It is an emirp because it is prime and its reverse (1237231044341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1434401327321 - 230 = 1433327585497 is a prime.
It is not a weakly prime, because it can be changed into another prime (1434401327351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717200663660 + 717200663661.
It is an arithmetic number, because the mean of its divisors is an integer number (717200663661).
Almost surely, 21434401327321 is an apocalyptic number.
It is an amenable number.
1434401327321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434401327321 is an equidigital number, since it uses as much as digits as its factorization.
1434401327321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 1434401327321 in words is "one trillion, four hundred thirty-four billion, four hundred one million, three hundred twenty-seven thousand, three hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •