14344045231 has 4 divisors (see below), whose sum is σ = 15098995000. Its totient is φ = 13589095464.

The previous prime is 14344045229. The next prime is 14344045253. The reversal of 14344045231 is 13254044341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13254044341 = 131 ⋅101175911.

It is a cyclic number.

It is not a de Polignac number, because 14344045231 - 2¹ = 14344045229 is a prime.

It is a super-2 number, since 2×14344045231² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14344045193 and 14344045202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14344045211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 377474856 + ... + 377474893.

It is an arithmetic number, because the mean of its divisors is an integer number (3774748750).

Almost surely, 2^14344045231 is an apocalyptic number.

14344045231 is a deficient number, since it is larger than the sum of its proper divisors (754949769).

14344045231 is an equidigital number, since it uses as much as digits as its factorization.

14344045231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 754949768.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 14344045231 its reverse (13254044341), we get a palindrome (27598089572).

The spelling of 14344045231 in words is "fourteen billion, three hundred forty-four million, forty-five thousand, two hundred thirty-one".