Base | Representation |
---|---|
bin | 1101000010111100101110… |
… | …0100011000000101101100 |
3 | 1212210022011201000200221120 |
4 | 3100233023210120011230 |
5 | 3340004122121041134 |
6 | 50301404025100540 |
7 | 3010225254460464 |
oct | 320571344300554 |
9 | 55708151020846 |
10 | 14344311112044 |
11 | 463042a738241 |
12 | 1738034927750 |
13 | 800880045384 |
14 | 3783a8558ba4 |
15 | 19d1dd7c0649 |
hex | d0bcb91816c |
14344311112044 has 24 divisors (see below), whose sum is σ = 33491750853120. Its totient is φ = 4778338238544.
The previous prime is 14344311111971. The next prime is 14344311112139. The reversal of 14344311112044 is 44021111344341.
It is a super-2 number, since 2×143443111120442 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14344311111996 and 14344311112014.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 387330564 + ... + 387367595.
It is an arithmetic number, because the mean of its divisors is an integer number (1395489618880).
Almost surely, 214344311112044 is an apocalyptic number.
It is an amenable number.
14344311112044 is an abundant number, since it is smaller than the sum of its proper divisors (19147439741076).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14344311112044 is a wasteful number, since it uses less digits than its factorization.
14344311112044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 774699709 (or 774699707 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 14344311112044 its reverse (44021111344341), we get a palindrome (58365422456385).
The spelling of 14344311112044 in words is "fourteen trillion, three hundred forty-four billion, three hundred eleven million, one hundred twelve thousand, forty-four".
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