Base | Representation |
---|---|
bin | 10100110111111011011… |
… | …110111100010010001111 |
3 | 12002010112211010211100212 |
4 | 110313323132330102033 |
5 | 142000214441131111 |
6 | 3014550230113035 |
7 | 205430561614145 |
oct | 24677336742217 |
9 | 5063484124325 |
10 | 1434443302031 |
11 | 503386936963 |
12 | 1b20081ab77b |
13 | a53626b376c |
14 | 4d5dac01595 |
15 | 274a6dc798b |
hex | 14dfb7bc48f |
1434443302031 has 32 divisors (see below), whose sum is σ = 1521622454400. Its totient is φ = 1350261964800.
The previous prime is 1434443302009. The next prime is 1434443302049. The reversal of 1434443302031 is 1302033444341.
It is a cyclic number.
It is not a de Polignac number, because 1434443302031 - 222 = 1434439107727 is a prime.
It is a super-2 number, since 2×14344433020312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434443302051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 138334415 + ... + 138344783.
It is an arithmetic number, because the mean of its divisors is an integer number (47550701700).
Almost surely, 21434443302031 is an apocalyptic number.
1434443302031 is a deficient number, since it is larger than the sum of its proper divisors (87179152369).
1434443302031 is a wasteful number, since it uses less digits than its factorization.
1434443302031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11219.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 1434443302031 its reverse (1302033444341), we get a palindrome (2736476746372).
The spelling of 1434443302031 in words is "one trillion, four hundred thirty-four billion, four hundred forty-three million, three hundred two thousand, thirty-one".
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