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143445654481 is a prime number
BaseRepresentation
bin1000010110011000000…
…1101111101111010001
3111201020222022021002211
42011212001233233101
54322234041420411
6145521550112121
713235500642123
oct2054601575721
9451228267084
10143445654481
1155920372378
12239737ab641
13106b06b12bc
146d2b0c1213
153ae8496221
hex216606fbd1

143445654481 has 2 divisors, whose sum is σ = 143445654482. Its totient is φ = 143445654480.

The previous prime is 143445654421. The next prime is 143445654493. The reversal of 143445654481 is 184456544341.

143445654481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141206850625 + 2238803856 = 375775^2 + 47316^2 .

It is a cyclic number.

It is not a de Polignac number, because 143445654481 - 217 = 143445523409 is a prime.

It is a super-2 number, since 2×1434456544812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143445654421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71722827240 + 71722827241.

It is an arithmetic number, because the mean of its divisors is an integer number (71722827241).

Almost surely, 2143445654481 is an apocalyptic number.

It is an amenable number.

143445654481 is a deficient number, since it is larger than the sum of its proper divisors (1).

143445654481 is an equidigital number, since it uses as much as digits as its factorization.

143445654481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3686400, while the sum is 49.

The spelling of 143445654481 in words is "one hundred forty-three billion, four hundred forty-five million, six hundred fifty-four thousand, four hundred eighty-one".