Base | Representation |
---|---|
bin | 11010101110000000… |
… | …11110011011110101 |
3 | 1101000200222102201202 |
4 | 31113000132123311 |
5 | 213334212104331 |
6 | 10331223302245 |
7 | 1015321315346 |
oct | 152700363365 |
9 | 41020872652 |
10 | 14344644341 |
11 | 60a11a5675 |
12 | 2943baa985 |
13 | 1477b3b441 |
14 | 9a118c0cd |
15 | 58e50eecb |
hex | 35701e6f5 |
14344644341 has 4 divisors (see below), whose sum is σ = 14377025472. Its totient is φ = 14312263212.
The previous prime is 14344644329. The next prime is 14344644371.
14344644341 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14344644341 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14344644295 and 14344644304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14344644311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16189901 + ... + 16190786.
It is an arithmetic number, because the mean of its divisors is an integer number (3594256368).
Almost surely, 214344644341 is an apocalyptic number.
It is an amenable number.
14344644341 is a deficient number, since it is larger than the sum of its proper divisors (32381131).
14344644341 is an equidigital number, since it uses as much as digits as its factorization.
14344644341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32381130.
The product of its digits is 221184, while the sum is 38.
The spelling of 14344644341 in words is "fourteen billion, three hundred forty-four million, six hundred forty-four thousand, three hundred forty-one".
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