Base | Representation |
---|---|
bin | 1101000011000011001011… |
… | …0100011000111111000111 |
3 | 1212210110122102120011220102 |
4 | 3100300302310120333013 |
5 | 3340021144100111041 |
6 | 50302251545154315 |
7 | 3010316220405554 |
oct | 320606264307707 |
9 | 55713572504812 |
10 | 14346043363271 |
11 | 4631139529224 |
12 | 1738438a8b99b |
13 | 800a97ba44b9 |
14 | 3784d0637a2b |
15 | 19d2908e509b |
hex | d0c32d18fc7 |
14346043363271 has 4 divisors (see below), whose sum is σ = 14346365653200. Its totient is φ = 14345721073344.
The previous prime is 14346043363231. The next prime is 14346043363313. The reversal of 14346043363271 is 17236334064341.
14346043363271 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14346043363271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14346043363231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161078186 + ... + 161167223.
It is an arithmetic number, because the mean of its divisors is an integer number (3586591413300).
Almost surely, 214346043363271 is an apocalyptic number.
14346043363271 is a deficient number, since it is larger than the sum of its proper divisors (322289929).
14346043363271 is an equidigital number, since it uses as much as digits as its factorization.
14346043363271 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 322289928.
The product of its (nonzero) digits is 2612736, while the sum is 47.
The spelling of 14346043363271 in words is "fourteen trillion, three hundred forty-six billion, forty-three million, three hundred sixty-three thousand, two hundred seventy-one".
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