Base | Representation |
---|---|
bin | 10100111000001111000… |
… | …111110000111101010011 |
3 | 12002011101210002120100001 |
4 | 110320033013300331103 |
5 | 142001403312130033 |
6 | 3015043035510431 |
7 | 205442002220062 |
oct | 24701707607523 |
9 | 5064353076301 |
10 | 1434772770643 |
11 | 503535908573 |
12 | 1b209a5b8417 |
13 | a53b5a2b6c4 |
14 | 4d62c8861d9 |
15 | 274c5ca7e7d |
hex | 14e0f1f0f53 |
1434772770643 has 2 divisors, whose sum is σ = 1434772770644. Its totient is φ = 1434772770642.
The previous prime is 1434772770623. The next prime is 1434772770649. The reversal of 1434772770643 is 3460772774341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1434772770643 is a prime.
It is not a weakly prime, because it can be changed into another prime (1434772770649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717386385321 + 717386385322.
It is an arithmetic number, because the mean of its divisors is an integer number (717386385322).
Almost surely, 21434772770643 is an apocalyptic number.
1434772770643 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434772770643 is an equidigital number, since it uses as much as digits as its factorization.
1434772770643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16595712, while the sum is 55.
The spelling of 1434772770643 in words is "one trillion, four hundred thirty-four billion, seven hundred seventy-two million, seven hundred seventy thousand, six hundred forty-three".
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