Base | Representation |
---|---|
bin | 1101000011010010010101… |
… | …0101111101101100101011 |
3 | 1212210212010222220002002121 |
4 | 3100310211111331230223 |
5 | 3340103012214010132 |
6 | 50304203415412111 |
7 | 3010522105363204 |
oct | 320644525755453 |
9 | 55725128802077 |
10 | 14350112250667 |
11 | 4632937293586 |
12 | 1739193684037 |
13 | 801295b6518b |
14 | 378798ba05ab |
15 | 19d42cc26497 |
hex | d0d2557db2b |
14350112250667 has 2 divisors, whose sum is σ = 14350112250668. Its totient is φ = 14350112250666.
The previous prime is 14350112250589. The next prime is 14350112250671. The reversal of 14350112250667 is 76605221105341.
It is a strong prime.
It is an emirp because it is prime and its reverse (76605221105341) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14350112250667 is a prime.
It is a super-2 number, since 2×143501122506672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14350112250167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7175056125333 + 7175056125334.
It is an arithmetic number, because the mean of its divisors is an integer number (7175056125334).
Almost surely, 214350112250667 is an apocalyptic number.
14350112250667 is a deficient number, since it is larger than the sum of its proper divisors (1).
14350112250667 is an equidigital number, since it uses as much as digits as its factorization.
14350112250667 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 14350112250667 in words is "fourteen trillion, three hundred fifty billion, one hundred twelve million, two hundred fifty thousand, six hundred sixty-seven".
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