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14352412013351 = 53212659403621
BaseRepresentation
bin1101000011011010111001…
…1010110111001100100111
31212211002002021022010102022
43100312232122313030213
53340122214433411401
650305223531333355
73010633102135526
oct320665632671447
955732067263368
1014352412013351
1146339074622a5
1217397158b125b
138015714562b9
143789363aa4bd
1519d514a9c71b
hexd0dae6b7327

14352412013351 has 12 divisors (see below), whose sum is σ = 14629513490760. Its totient is φ = 14080464521760.

The previous prime is 14352412013347. The next prime is 14352412013371. The reversal of 14352412013351 is 15331021425341.

It is not a de Polignac number, because 14352412013351 - 22 = 14352412013347 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14352412013321) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 35357321 + ... + 35760941.

It is an arithmetic number, because the mean of its divisors is an integer number (1219126124230).

Almost surely, 214352412013351 is an apocalyptic number.

14352412013351 is a deficient number, since it is larger than the sum of its proper divisors (277101477409).

14352412013351 is an equidigital number, since it uses as much as digits as its factorization.

14352412013351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 416386 (or 416333 counting only the distinct ones).

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 14352412013351 its reverse (15331021425341), we get a palindrome (29683433438692).

The spelling of 14352412013351 in words is "fourteen trillion, three hundred fifty-two billion, four hundred twelve million, thirteen thousand, three hundred fifty-one".

Divisors: 1 53 2809 12659 403621 670927 21391913 35559131 1133771389 5109438239 270800226667 14352412013351