Search a number
-
+
143524241153 is a prime number
BaseRepresentation
bin1000010110101010110…
…1100001111100000001
3111201110110011212202022
42011222231201330001
54322414201204103
6145533434331225
713240443630566
oct2055255417401
9451413155668
10143524241153
1155960768737
1223995b89b15
13106c3a682a7
146d376da86d
153b0031b138
hex216ab61f01

143524241153 has 2 divisors, whose sum is σ = 143524241154. Its totient is φ = 143524241152.

The previous prime is 143524241117. The next prime is 143524241233. The reversal of 143524241153 is 351142425341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130069865104 + 13454376049 = 360652^2 + 115993^2 .

It is a cyclic number.

It is not a de Polignac number, because 143524241153 - 220 = 143523192577 is a prime.

It is not a weakly prime, because it can be changed into another prime (143524241053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71762120576 + 71762120577.

It is an arithmetic number, because the mean of its divisors is an integer number (71762120577).

Almost surely, 2143524241153 is an apocalyptic number.

It is an amenable number.

143524241153 is a deficient number, since it is larger than the sum of its proper divisors (1).

143524241153 is an equidigital number, since it uses as much as digits as its factorization.

143524241153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 57600, while the sum is 35.

Adding to 143524241153 its reverse (351142425341), we get a palindrome (494666666494).

The spelling of 143524241153 in words is "one hundred forty-three billion, five hundred twenty-four million, two hundred forty-one thousand, one hundred fifty-three".