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14353140257 is a prime number
BaseRepresentation
bin11010101111000001…
…11000101000100001
31101001021222001221022
431113200320220201
5213343400442012
610332125335225
71015453451651
oct152740705041
941037861838
1014353140257
1160a5a78795
122946a07515
131479824501
149a2360361
1559013c472
hex357838a21

14353140257 has 2 divisors, whose sum is σ = 14353140258. Its totient is φ = 14353140256.

The previous prime is 14353140253. The next prime is 14353140287. The reversal of 14353140257 is 75204135341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12284618896 + 2068521361 = 110836^2 + 45481^2 .

It is a cyclic number.

It is not a de Polignac number, because 14353140257 - 22 = 14353140253 is a prime.

It is a super-2 number, since 2×143531402572 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14353140253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7176570128 + 7176570129.

It is an arithmetic number, because the mean of its divisors is an integer number (7176570129).

Almost surely, 214353140257 is an apocalyptic number.

It is an amenable number.

14353140257 is a deficient number, since it is larger than the sum of its proper divisors (1).

14353140257 is an equidigital number, since it uses as much as digits as its factorization.

14353140257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 14353140257 its reverse (75204135341), we get a palindrome (89557275598).

The spelling of 14353140257 in words is "fourteen billion, three hundred fifty-three million, one hundred forty thousand, two hundred fifty-seven".