143540113 has 2 divisors, whose sum is σ = 143540114. Its totient is φ = 143540112.

The previous prime is 143540107. The next prime is 143540141. The reversal of 143540113 is 311045341.

143540113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97950609 + 45589504 = 9897^2 + 6752^2 .

It is a cyclic number.

It is not a de Polignac number, because 143540113 - 2⁵ = 143540081 is a prime.

It is not a weakly prime, because it can be changed into another prime (143540183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71770056 + 71770057.

It is an arithmetic number, because the mean of its divisors is an integer number (71770057).

Almost surely, 2^143540113 is an apocalyptic number.

It is an amenable number.

143540113 is a deficient number, since it is larger than the sum of its proper divisors (1).

143540113 is an equidigital number, since it uses as much as digits as its factorization.

143540113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 143540113 is about 11980.8227179940. The cubic root of 143540113 is about 523.5897000333.

Adding to 143540113 its reverse (311045341), we get a palindrome (454585454).

The spelling of 143540113 in words is "one hundred forty-three million, five hundred forty thousand, one hundred thirteen".