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14354104337 is a prime number
BaseRepresentation
bin11010101111001001…
…00100000000010001
31101001100210001101222
431113210210000101
5213344122314322
610332202134425
71015464605456
oct152744440021
941040701358
1014354104337
1160a6577051
1229471b1415
131479aa1281
149a253182d
1559027ce42
hex357924011

14354104337 has 2 divisors, whose sum is σ = 14354104338. Its totient is φ = 14354104336.

The previous prime is 14354104307. The next prime is 14354104357. The reversal of 14354104337 is 73340145341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12230369281 + 2123735056 = 110591^2 + 46084^2 .

It is a cyclic number.

It is not a de Polignac number, because 14354104337 - 218 = 14353842193 is a prime.

It is a super-2 number, since 2×143541043372 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14354104297 and 14354104306.

It is not a weakly prime, because it can be changed into another prime (14354104307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177052168 + 7177052169.

It is an arithmetic number, because the mean of its divisors is an integer number (7177052169).

Almost surely, 214354104337 is an apocalyptic number.

It is an amenable number.

14354104337 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354104337 is an equidigital number, since it uses as much as digits as its factorization.

14354104337 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 35.

Adding to 14354104337 its reverse (73340145341), we get a palindrome (87694249678).

The spelling of 14354104337 in words is "fourteen billion, three hundred fifty-four million, one hundred four thousand, three hundred thirty-seven".