Base | Representation |
---|---|
bin | 1101000011100001001111… |
… | …1000010100110010100001 |
3 | 1212211020110220022222022001 |
4 | 3100320103320110302201 |
5 | 3340134211221014203 |
6 | 50310104500044001 |
7 | 3011023221604501 |
oct | 320702370246241 |
9 | 55736426288261 |
10 | 14354114235553 |
11 | 4634600303004 |
12 | 1739b0b993601 |
13 | 801783000181 |
14 | 378a584ada01 |
15 | 19d5b423e91d |
hex | d0e13e14ca1 |
14354114235553 has 2 divisors, whose sum is σ = 14354114235554. Its totient is φ = 14354114235552.
The previous prime is 14354114235437. The next prime is 14354114235613. The reversal of 14354114235553 is 35553241145341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14005946972304 + 348167263249 = 3742452^2 + 590057^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14354114235553 is a prime.
It is not a weakly prime, because it can be changed into another prime (14354114235053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177057117776 + 7177057117777.
It is an arithmetic number, because the mean of its divisors is an integer number (7177057117777).
Almost surely, 214354114235553 is an apocalyptic number.
It is an amenable number.
14354114235553 is a deficient number, since it is larger than the sum of its proper divisors (1).
14354114235553 is an equidigital number, since it uses as much as digits as its factorization.
14354114235553 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2160000, while the sum is 46.
The spelling of 14354114235553 in words is "fourteen trillion, three hundred fifty-four billion, one hundred fourteen million, two hundred thirty-five thousand, five hundred fifty-three".
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