Base | Representation |
---|---|
bin | 1101000011100001010000… |
… | …1111100000110010111010 |
3 | 1212211020111022202210102021 |
4 | 3100320110033200302322 |
5 | 3340134214300022132 |
6 | 50310105234225054 |
7 | 3011023324352155 |
oct | 320702417406272 |
9 | 55736438683367 |
10 | 14354120314042 |
11 | 4634603784953 |
12 | 1739b11a2518a |
13 | 80178434ab02 |
14 | 378a59212c9c |
15 | 19d5b4a40997 |
hex | d0e143e0cba |
14354120314042 has 4 divisors (see below), whose sum is σ = 21531180471066. Its totient is φ = 7177060157020.
The previous prime is 14354120313961. The next prime is 14354120314043. The reversal of 14354120314042 is 24041302145341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10110689232361 + 4243431081681 = 3179731^2 + 2059959^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14354120313989 and 14354120314007.
It is not an unprimeable number, because it can be changed into a prime (14354120314043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3588530078509 + ... + 3588530078512.
Almost surely, 214354120314042 is an apocalyptic number.
14354120314042 is a deficient number, since it is larger than the sum of its proper divisors (7177060157024).
14354120314042 is an equidigital number, since it uses as much as digits as its factorization.
14354120314042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7177060157023.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 14354120314042 its reverse (24041302145341), we get a palindrome (38395422459383).
The spelling of 14354120314042 in words is "fourteen trillion, three hundred fifty-four billion, one hundred twenty million, three hundred fourteen thousand, forty-two".
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