Base | Representation |
---|---|
bin | 1101000011100100111111… |
… | …1000111000001001100001 |
3 | 1212211100002001202120210102 |
4 | 3100321033320320021201 |
5 | 3340143241434411340 |
6 | 50310352422512145 |
7 | 3011060165224640 |
oct | 320711770701141 |
9 | 55740061676712 |
10 | 14355121013345 |
11 | 4634a77636072 |
12 | 173a150b95655 |
13 | 8018b3771388 |
14 | 378b120a3357 |
15 | 19d62280e215 |
hex | d0e4fe38261 |
14355121013345 has 32 divisors (see below), whose sum is σ = 19759480747776. Its totient is φ = 9807309792000.
The previous prime is 14355121013341. The next prime is 14355121013353. The reversal of 14355121013345 is 54331012155341.
It is not a de Polignac number, because 14355121013345 - 22 = 14355121013341 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14355121013299 and 14355121013308.
It is not an unprimeable number, because it can be changed into a prime (14355121013341) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25303295 + ... + 25864395.
It is an arithmetic number, because the mean of its divisors is an integer number (617483773368).
Almost surely, 214355121013345 is an apocalyptic number.
It is an amenable number.
14355121013345 is a deficient number, since it is larger than the sum of its proper divisors (5404359734431).
14355121013345 is a wasteful number, since it uses less digits than its factorization.
14355121013345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 563801.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 14355121013345 its reverse (54331012155341), we get a palindrome (68686133168686).
The spelling of 14355121013345 in words is "fourteen trillion, three hundred fifty-five billion, one hundred twenty-one million, thirteen thousand, three hundred forty-five".
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