Base | Representation |
---|---|
bin | 11010101111010001… |
… | …11011101110000011 |
3 | 1101001102221021000211 |
4 | 31113220323232003 |
5 | 213344421000201 |
6 | 10332242454551 |
7 | 1015510416652 |
oct | 152750735603 |
9 | 41042837024 |
10 | 14355250051 |
11 | 60a718991a |
12 | 2947664457 |
13 | 147a0b28cc |
14 | 9a274d199 |
15 | 590407651 |
hex | 357a3bb83 |
14355250051 has 2 divisors, whose sum is σ = 14355250052. Its totient is φ = 14355250050.
The previous prime is 14355250003. The next prime is 14355250069. The reversal of 14355250051 is 15005255341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14355250051 - 211 = 14355248003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14355249995 and 14355250022.
It is not a weakly prime, because it can be changed into another prime (14355250081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177625025 + 7177625026.
It is an arithmetic number, because the mean of its divisors is an integer number (7177625026).
Almost surely, 214355250051 is an apocalyptic number.
14355250051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14355250051 is an equidigital number, since it uses as much as digits as its factorization.
14355250051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 14355250051 in words is "fourteen billion, three hundred fifty-five million, two hundred fifty thousand, fifty-one".
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