Base | Representation |
---|---|
bin | 1000010110110001110… |
… | …0001100101011001101 |
3 | 111201112110202210012210 |
4 | 2011230130030223031 |
5 | 4322444113031140 |
6 | 145540352221033 |
7 | 13241245336500 |
oct | 2055434145315 |
9 | 451473683183 |
10 | 143553252045 |
11 | 55976082a85 |
12 | 239a383a779 |
13 | 106c9a84cb8 |
14 | 6d3b4cd137 |
15 | 3b02b4bd80 |
hex | 216c70cacd |
143553252045 has 24 divisors (see below), whose sum is σ = 267184829664. Its totient is φ = 65624343456.
The previous prime is 143553252041. The next prime is 143553252079. The reversal of 143553252045 is 540252355341.
It is not a de Polignac number, because 143553252045 - 22 = 143553252041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143553251994 and 143553252012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143553252041) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 97654539 + ... + 97656008.
It is an arithmetic number, because the mean of its divisors is an integer number (11132701236).
Almost surely, 2143553252045 is an apocalyptic number.
143553252045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
143553252045 is a deficient number, since it is larger than the sum of its proper divisors (123631577619).
143553252045 is a wasteful number, since it uses less digits than its factorization.
143553252045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195310569 (or 195310562 counting only the distinct ones).
The product of its (nonzero) digits is 360000, while the sum is 39.
The spelling of 143553252045 in words is "one hundred forty-three billion, five hundred fifty-three million, two hundred fifty-two thousand, forty-five".
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