Base | Representation |
---|---|
bin | 1101000011100110100111… |
… | …0010100001100000001101 |
3 | 1212211101012100102121100102 |
4 | 3100321221302201200031 |
5 | 3340200134210232331 |
6 | 50310503504340445 |
7 | 3011104022613140 |
oct | 320715162414015 |
9 | 55741170377312 |
10 | 14355555555341 |
11 | 463517a953990 |
12 | 173a252614725 |
13 | 8019527b8110 |
14 | 378b53a9a057 |
15 | 19d64aa474cb |
hex | d0e69ca180d |
14355555555341 has 32 divisors (see below), whose sum is σ = 19316769040128. Its totient is φ = 10303079523840.
The previous prime is 14355555555323. The next prime is 14355555555379.
14355555555341 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 14355555555341 - 210 = 14355555554317 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14355555555311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15233150 + ... + 16148063.
It is an arithmetic number, because the mean of its divisors is an integer number (603649032504).
Almost surely, 214355555555341 is an apocalyptic number.
14355555555341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
14355555555341 is a deficient number, since it is larger than the sum of its proper divisors (4961213484787).
14355555555341 is a wasteful number, since it uses less digits than its factorization.
14355555555341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31381701.
The product of its digits is 56250000, while the sum is 56.
The spelling of 14355555555341 in words is "fourteen trillion, three hundred fifty-five billion, five hundred fifty-five million, five hundred fifty-five thousand, three hundred forty-one".
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