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143601161113 is a prime number
BaseRepresentation
bin1000010110111101001…
…0111101001110011001
3111201122210220211002201
42011233102331032121
54323043344123423
6145545223130201
713242366505204
oct2055722751631
9451583824081
10143601161113
11559a0125853
12239b78a3961
131070698a767
146d43a0093b
153b06e622ad
hex216f4bd399

143601161113 has 2 divisors, whose sum is σ = 143601161114. Its totient is φ = 143601161112.

The previous prime is 143601161083. The next prime is 143601161129. The reversal of 143601161113 is 311161106341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86290237504 + 57310923609 = 293752^2 + 239397^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143601161113 is a prime.

It is not a weakly prime, because it can be changed into another prime (143601161153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71800580556 + 71800580557.

It is an arithmetic number, because the mean of its divisors is an integer number (71800580557).

Almost surely, 2143601161113 is an apocalyptic number.

It is an amenable number.

143601161113 is a deficient number, since it is larger than the sum of its proper divisors (1).

143601161113 is an equidigital number, since it uses as much as digits as its factorization.

143601161113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 28.

Adding to 143601161113 its reverse (311161106341), we get a palindrome (454762267454).

The spelling of 143601161113 in words is "one hundred forty-three billion, six hundred one million, one hundred sixty-one thousand, one hundred thirteen".