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143634413029417 is a prime number
BaseRepresentation
bin100000101010001001111110…
…001010101000100000101001
3200211120022112012112220012121
4200222021332022220200221
5122311301234213420132
61225252423255311241
742153146440233052
oct4052117612504051
9624508465486177
10143634413029417
11418480156828a2
121413938a37b521
13621b8896085ab
142767d2aa1d729
1511913d9d36497
hex82a27e2a8829

143634413029417 has 2 divisors, whose sum is σ = 143634413029418. Its totient is φ = 143634413029416.

The previous prime is 143634413029343. The next prime is 143634413029421. The reversal of 143634413029417 is 714920314436341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102011838208281 + 41622574821136 = 10100091^2 + 6451556^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143634413029417 is a prime.

It is not a weakly prime, because it can be changed into another prime (143634413029447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71817206514708 + 71817206514709.

It is an arithmetic number, because the mean of its divisors is an integer number (71817206514709).

Almost surely, 2143634413029417 is an apocalyptic number.

It is an amenable number.

143634413029417 is a deficient number, since it is larger than the sum of its proper divisors (1).

143634413029417 is an equidigital number, since it uses as much as digits as its factorization.

143634413029417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5225472, while the sum is 52.

The spelling of 143634413029417 in words is "one hundred forty-three trillion, six hundred thirty-four billion, four hundred thirteen million, twenty-nine thousand, four hundred seventeen".