Base | Representation |
---|---|
bin | 1000010111000111000… |
… | …0101101000000000011 |
3 | 111201202200201201210022 |
4 | 2011301300231000003 |
5 | 4323134440412121 |
6 | 145553301324055 |
7 | 13243411134635 |
oct | 2056160550003 |
9 | 451680651708 |
10 | 143642513411 |
11 | 55a114aa401 |
12 | 23a0970662b |
13 | 10712408987 |
14 | 6d492c6a55 |
15 | 3b0a8ceaab |
hex | 2171c2d003 |
143642513411 has 2 divisors, whose sum is σ = 143642513412. Its totient is φ = 143642513410.
The previous prime is 143642513351. The next prime is 143642513423. The reversal of 143642513411 is 114315246341.
It is a strong prime.
It is an emirp because it is prime and its reverse (114315246341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 143642513411 - 218 = 143642251267 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (143642513461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71821256705 + 71821256706.
It is an arithmetic number, because the mean of its divisors is an integer number (71821256706).
Almost surely, 2143642513411 is an apocalyptic number.
143642513411 is a deficient number, since it is larger than the sum of its proper divisors (1).
143642513411 is an equidigital number, since it uses as much as digits as its factorization.
143642513411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34560, while the sum is 35.
Adding to 143642513411 its reverse (114315246341), we get a palindrome (257957759752).
The spelling of 143642513411 in words is "one hundred forty-three billion, six hundred forty-two million, five hundred thirteen thousand, four hundred eleven".
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