143647530072961 has 2 divisors, whose sum is σ = 143647530072962. Its totient is φ = 143647530072960.

The previous prime is 143647530072803. The next prime is 143647530072967. The reversal of 143647530072961 is 169270035746341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94432604910736 + 49214925162225 = 9717644^2 + 7015335^2 .

It is a cyclic number.

It is not a de Polignac number, because 143647530072961 - 2¹³ = 143647530064769 is a prime.

It is a super-3 number, since 3×143647530072961³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 143647530072896 and 143647530072905.

It is not a weakly prime, because it can be changed into another prime (143647530072967) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71823765036480 + 71823765036481.

It is an arithmetic number, because the mean of its divisors is an integer number (71823765036481).

Almost surely, 2^{143647530072961} is an apocalyptic number.

It is an amenable number.

143647530072961 is a deficient number, since it is larger than the sum of its proper divisors (1).

143647530072961 is an equidigital number, since it uses as much as digits as its factorization.

143647530072961 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22861440, while the sum is 58.

The spelling of 143647530072961 in words is "one hundred forty-three trillion, six hundred forty-seven billion, five hundred thirty million, seventy-two thousand, nine hundred sixty-one".