Base | Representation |
---|---|
bin | 1101000100001001110011… |
… | …0001011111100101010111 |
3 | 1212212021120121102200200201 |
4 | 3101002130301133211113 |
5 | 3340324010204423233 |
6 | 50315105034121331 |
7 | 3011560053430411 |
oct | 321023461374527 |
9 | 55767517380621 |
10 | 14365000857943 |
11 | 463918754259a |
12 | 1740049880247 |
13 | 8027c95abc78 |
14 | 3793ac2a99b1 |
15 | 19d9eed8577d |
hex | d109cc5f957 |
14365000857943 has 4 divisors (see below), whose sum is σ = 14365008889848. Its totient is φ = 14364992826040.
The previous prime is 14365000857931. The next prime is 14365000858051. The reversal of 14365000857943 is 34975800056341.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 14365000857943 - 217 = 14365000726871 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14365000857143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16380 + ... + 5360062.
It is an arithmetic number, because the mean of its divisors is an integer number (3591252222462).
Almost surely, 214365000857943 is an apocalyptic number.
14365000857943 is a deficient number, since it is larger than the sum of its proper divisors (8031905).
14365000857943 is an equidigital number, since it uses as much as digits as its factorization.
14365000857943 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8031904.
The product of its (nonzero) digits is 10886400, while the sum is 55.
The spelling of 14365000857943 in words is "fourteen trillion, three hundred sixty-five billion, eight hundred fifty-seven thousand, nine hundred forty-three".
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