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143651800484713 is a prime number
BaseRepresentation
bin100000101010011010001010…
…100010100000101101101001
3200211121222101222010010212101
4200222122022202200231221
5122312042341411002323
61225304420501013401
742154333350200413
oct4052321242405551
9624558358103771
10143651800484713
1141854428419364
12141408213b4261
1362203ca96a391
142768ad9d599b3
151191aa6544dad
hex82a68a8a0b69

143651800484713 has 2 divisors, whose sum is σ = 143651800484714. Its totient is φ = 143651800484712.

The previous prime is 143651800484609. The next prime is 143651800484719. The reversal of 143651800484713 is 317484008156341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123590646139689 + 20061154345024 = 11117133^2 + 4478968^2 .

It is a cyclic number.

It is not a de Polignac number, because 143651800484713 - 241 = 141452777229161 is a prime.

It is not a weakly prime, because it can be changed into another prime (143651800484719) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71825900242356 + 71825900242357.

It is an arithmetic number, because the mean of its divisors is an integer number (71825900242357).

Almost surely, 2143651800484713 is an apocalyptic number.

It is an amenable number.

143651800484713 is a deficient number, since it is larger than the sum of its proper divisors (1).

143651800484713 is an equidigital number, since it uses as much as digits as its factorization.

143651800484713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7741440, while the sum is 55.

The spelling of 143651800484713 in words is "one hundred forty-three trillion, six hundred fifty-one billion, eight hundred million, four hundred eighty-four thousand, seven hundred thirteen".