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1439000118 = 23279944451
BaseRepresentation
bin101010111000101…
…0110011000110110
310201021201210001200
41111301112120312
510421341000433
6354442433330
750442204423
oct12561263066
93637653050
101439000118
116793070a6
12341b02846
1319c18517a
14d9184d4a
15864ea613
hex55c56636

1439000118 has 12 divisors (see below), whose sum is σ = 3117833628. Its totient is φ = 479666700.

The previous prime is 1439000111. The next prime is 1439000159. The reversal of 1439000118 is 8110009341.

It is a junction number, because it is equal to n+sod(n) for n = 1439000091 and 1439000100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1439000111) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 39972208 + ... + 39972243.

It is an arithmetic number, because the mean of its divisors is an integer number (259819469).

Almost surely, 21439000118 is an apocalyptic number.

1439000118 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

1439000118 is an abundant number, since it is smaller than the sum of its proper divisors (1678833510).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1439000118 is a wasteful number, since it uses less digits than its factorization.

1439000118 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79944459 (or 79944456 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 27.

The square root of 1439000118 is about 37934.1550321079. The cubic root of 1439000118 is about 1128.9818060873.

Adding to 1439000118 its reverse (8110009341), we get a palindrome (9549009459).

The spelling of 1439000118 in words is "one billion, four hundred thirty-nine million, one hundred eighteen", and thus it is an aban number.

Divisors: 1 2 3 6 9 18 79944451 159888902 239833353 479666706 719500059 1439000118