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143926440433 is a prime number
BaseRepresentation
bin1000011000001010101…
…1110011000111110001
3111202111110222201102221
42012002223303013301
54324230132043213
6150041403041041
713253426362336
oct2060253630761
9452443881387
10143926440433
11560477a5a36
1223a88810181
1310759199929
146d74cb498d
153b257b638d
hex2182af31f1

143926440433 has 2 divisors, whose sum is σ = 143926440434. Its totient is φ = 143926440432.

The previous prime is 143926440391. The next prime is 143926440479. The reversal of 143926440433 is 334044629341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81697645584 + 62228794849 = 285828^2 + 249457^2 .

It is an emirp because it is prime and its reverse (334044629341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143926440433 - 225 = 143892886001 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 143926440433.

It is not a weakly prime, because it can be changed into another prime (143926440233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71963220216 + 71963220217.

It is an arithmetic number, because the mean of its divisors is an integer number (71963220217).

Almost surely, 2143926440433 is an apocalyptic number.

It is an amenable number.

143926440433 is a deficient number, since it is larger than the sum of its proper divisors (1).

143926440433 is an equidigital number, since it uses as much as digits as its factorization.

143926440433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 746496, while the sum is 43.

The spelling of 143926440433 in words is "one hundred forty-three billion, nine hundred twenty-six million, four hundred forty thousand, four hundred thirty-three".