14400113115131 has 4 divisors (see below), whose sum is σ = 14400455422152. Its totient is φ = 14399770808112.

The previous prime is 14400113115049. The next prime is 14400113115139. The reversal of 14400113115131 is 13151131100441.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14400113115131 is a prime.

It is a super-2 number, since 2×14400113115131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14400113115131.

It is not an unprimeable number, because it can be changed into a prime (14400113115139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171090401 + ... + 171174546.

It is an arithmetic number, because the mean of its divisors is an integer number (3600113855538).

Almost surely, 2^{14400113115131} is an apocalyptic number.

14400113115131 is a deficient number, since it is larger than the sum of its proper divisors (342307021).

14400113115131 is an equidigital number, since it uses as much as digits as its factorization.

14400113115131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 342307020.

The product of its (nonzero) digits is 720, while the sum is 26.

Adding to 14400113115131 its reverse (13151131100441), we get a palindrome (27551244215572).

The spelling of 14400113115131 in words is "fourteen trillion, four hundred billion, one hundred thirteen million, one hundred fifteen thousand, one hundred thirty-one".