14400113115132 has 18 divisors (see below), whose sum is σ = 36400285930008. Its totient is φ = 4800037705032.

The previous prime is 14400113115049. The next prime is 14400113115139. The reversal of 14400113115132 is 23151131100441.

14400113115132 is a `hidden beast` number, since 1 + 4 + 400 + 1 + 13 + 115 + 132 = 666.

It is a tau number, because it is divible by the number of its divisors (18).

It is a junction number, because it is equal to n+sod(n) for n = 14400113115096 and 14400113115105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14400113115139) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 200001571008 + ... + 200001571079.

Almost surely, 2^{14400113115132} is an apocalyptic number.

14400113115132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

14400113115132 is an abundant number, since it is smaller than the sum of its proper divisors (22000172814876).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14400113115132 is a wasteful number, since it uses less digits than its factorization.

14400113115132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400003142097 (or 400003142092 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 14400113115132 its reverse (23151131100441), we get a palindrome (37551244215573).

The spelling of 14400113115132 in words is "fourteen trillion, four hundred billion, one hundred thirteen million, one hundred fifteen thousand, one hundred thirty-two".