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144004110355302 = 23151158944934167
BaseRepresentation
bin100000101111100010010001…
…110110000000101101100110
3200212212122210001021220222220
4200233202101312000231212
5122333330404222332202
61230134324112133210
742221645045530311
oct4057422166005546
9625778701256886
10144004110355302
114197a88913066a
1214198b65237206
1362476b5c58822
14277bb9c4a9978
15119ad26269abc
hex82f891d80b66

144004110355302 has 16 divisors (see below), whose sum is σ = 289915559922432. Its totient is φ = 47683480249800.

The previous prime is 144004110355241. The next prime is 144004110355327. The reversal of 144004110355302 is 203553011400441.

It is a super-2 number, since 2×1440041103553022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79472466178 + ... + 79472467989.

It is an arithmetic number, because the mean of its divisors is an integer number (18119722495152).

Almost surely, 2144004110355302 is an apocalyptic number.

144004110355302 is an abundant number, since it is smaller than the sum of its proper divisors (145911449567130).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

144004110355302 is a wasteful number, since it uses less digits than its factorization.

144004110355302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 158944934323.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 144004110355302 its reverse (203553011400441), we get a palindrome (347557121755743).

The spelling of 144004110355302 in words is "one hundred forty-four trillion, four billion, one hundred ten million, three hundred fifty-five thousand, three hundred two".

Divisors: 1 2 3 6 151 302 453 906 158944934167 317889868334 476834802501 953669605002 24000685059217 48001370118434 72002055177651 144004110355302