Base | Representation |
---|---|
bin | 11010110100110000… |
… | …10001001001001011 |
3 | 1101011122102102100101 |
4 | 31122120101021023 |
5 | 213443202304003 |
6 | 10341003550231 |
7 | 1016606201512 |
oct | 153230211113 |
9 | 41148372311 |
10 | 14401213003 |
11 | 6120122531 |
12 | 295ab2b377 |
13 | 1486786618 |
14 | 9a88b5679 |
15 | 59448611d |
hex | 35a61124b |
14401213003 has 2 divisors, whose sum is σ = 14401213004. Its totient is φ = 14401213002.
The previous prime is 14401212971. The next prime is 14401213007. The reversal of 14401213003 is 30031210441.
It is a strong prime.
It is an emirp because it is prime and its reverse (30031210441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14401213003 - 25 = 14401212971 is a prime.
It is not a weakly prime, because it can be changed into another prime (14401213007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200606501 + 7200606502.
It is an arithmetic number, because the mean of its divisors is an integer number (7200606502).
Almost surely, 214401213003 is an apocalyptic number.
14401213003 is a deficient number, since it is larger than the sum of its proper divisors (1).
14401213003 is an equidigital number, since it uses as much as digits as its factorization.
14401213003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 14401213003 its reverse (30031210441), we get a palindrome (44432423444).
The spelling of 14401213003 in words is "fourteen billion, four hundred one million, two hundred thirteen thousand, three".
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