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144012241 is a prime number
BaseRepresentation
bin10001001010101…
…11001111010001
3101000222120122201
420211113033101
5243331342431
622142403201
73366040522
oct1045271721
9330876581
10144012241
117432258a
1240290501
1323ab3659
14151aa849
15c99a461
hex89573d1

144012241 has 2 divisors, whose sum is σ = 144012242. Its totient is φ = 144012240.

The previous prime is 144012233. The next prime is 144012247. The reversal of 144012241 is 142210441.

144012241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88435216 + 55577025 = 9404^2 + 7455^2 .

It is a cyclic number.

It is not a de Polignac number, because 144012241 - 23 = 144012233 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (144012247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72006120 + 72006121.

It is an arithmetic number, because the mean of its divisors is an integer number (72006121).

Almost surely, 2144012241 is an apocalyptic number.

It is an amenable number.

144012241 is a deficient number, since it is larger than the sum of its proper divisors (1).

144012241 is an equidigital number, since it uses as much as digits as its factorization.

144012241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 19.

The square root of 144012241 is about 12000.5100308279. The cubic root of 144012241 is about 524.1631305022.

Adding to 144012241 its reverse (142210441), we get a palindrome (286222682).

The spelling of 144012241 in words is "one hundred forty-four million, twelve thousand, two hundred forty-one".