Base | Representation |
---|---|
bin | 1101000110010000110010… |
… | …0001101100010011111110 |
3 | 1212222202002212022100100001 |
4 | 3101210030201230103332 |
5 | 3341422212242033314 |
6 | 50343500344224514 |
7 | 3014312020013152 |
oct | 321441441542376 |
9 | 55882085270301 |
10 | 14401235502334 |
11 | 465259100219a |
12 | 174708076b13a |
13 | 806052537055 |
14 | 37b048763062 |
15 | 19e920ee6674 |
hex | d190c86c4fe |
14401235502334 has 4 divisors (see below), whose sum is σ = 21601853253504. Its totient is φ = 7200617751166.
The previous prime is 14401235502331. The next prime is 14401235502413. The reversal of 14401235502334 is 43320553210441.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 14401235502293 and 14401235502302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14401235502331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3600308875582 + ... + 3600308875585.
It is an arithmetic number, because the mean of its divisors is an integer number (5400463313376).
Almost surely, 214401235502334 is an apocalyptic number.
14401235502334 is a deficient number, since it is larger than the sum of its proper divisors (7200617751170).
14401235502334 is an equidigital number, since it uses as much as digits as its factorization.
14401235502334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7200617751169.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 14401235502334 its reverse (43320553210441), we get a palindrome (57721788712775).
It can be divided in two parts, 144012 and 35502334, that added together give a triangular number (35646346 = T8443).
The spelling of 14401235502334 in words is "fourteen trillion, four hundred one billion, two hundred thirty-five million, five hundred two thousand, three hundred thirty-four".
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