Base | Representation |
---|---|
bin | 1101000110010001000001… |
… | …1111110101000000101011 |
3 | 1212222202021111200000002001 |
4 | 3101210100133311000223 |
5 | 3341422331320410124 |
6 | 50343511124151431 |
7 | 3014313456202153 |
oct | 321442037650053 |
9 | 55882244600061 |
10 | 14401302122539 |
11 | 4652615674a12 |
12 | 174709ab38577 |
13 | 8060632913a7 |
14 | 37b053545763 |
15 | 19e926ca5b44 |
hex | d19107f502b |
14401302122539 has 2 divisors, whose sum is σ = 14401302122540. Its totient is φ = 14401302122538.
The previous prime is 14401302122509. The next prime is 14401302122563. The reversal of 14401302122539 is 93522120310441.
It is a strong prime.
It is an emirp because it is prime and its reverse (93522120310441) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14401302122539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14401302122498 and 14401302122507.
It is not a weakly prime, because it can be changed into another prime (14401302122509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200651061269 + 7200651061270.
It is an arithmetic number, because the mean of its divisors is an integer number (7200651061270).
Almost surely, 214401302122539 is an apocalyptic number.
14401302122539 is a deficient number, since it is larger than the sum of its proper divisors (1).
14401302122539 is an equidigital number, since it uses as much as digits as its factorization.
14401302122539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 14401302122539 in words is "fourteen trillion, four hundred one billion, three hundred two million, one hundred twenty-two thousand, five hundred thirty-nine".
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