144013223232 has 168 divisors, whose sum is σ = 441638801760. Its totient is φ = 44732113920.

The previous prime is 144013223183. The next prime is 144013223297. The reversal of 144013223232 is 232322310441.

144013223232 is a `hidden beast` number, since 1 + 4 + 401 + 3 + 2 + 23 + 232 = 666.

144013223232 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 144013223196 and 144013223205.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 559723 + ... + 775445.

Almost surely, 2^144013223232 is an apocalyptic number.

144013223232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 144013223232, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (220819400880).

144013223232 is an abundant number, since it is smaller than the sum of its proper divisors (297625578528).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

144013223232 is a wasteful number, since it uses less digits than its factorization.

144013223232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215821 (or 215808 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 144013223232 its reverse (232322310441), we get a palindrome (376335533673).

The spelling of 144013223232 in words is "one hundred forty-four billion, thirteen million, two hundred twenty-three thousand, two hundred thirty-two".