Base | Representation |
---|---|
bin | 1101000110010001001101… |
… | …1101000011100010010011 |
3 | 1212222202101222000011221121 |
4 | 3101210103131003202103 |
5 | 3341422432020233001 |
6 | 50343520055303111 |
7 | 3014314630632256 |
oct | 321442335034223 |
9 | 55882358004847 |
10 | 14401351727251 |
11 | 4652640675745 |
12 | 17470b367aa97 |
13 | 80607063b8a8 |
14 | 37b059d7909d |
15 | 19e92b3036a1 |
hex | d1913743893 |
14401351727251 has 2 divisors, whose sum is σ = 14401351727252. Its totient is φ = 14401351727250.
The previous prime is 14401351727179. The next prime is 14401351727369. The reversal of 14401351727251 is 15272715310441.
It is a weak prime.
It is an emirp because it is prime and its reverse (15272715310441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14401351727251 - 211 = 14401351725203 is a prime.
It is a super-2 number, since 2×144013517272512 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14401351727198 and 14401351727207.
It is not a weakly prime, because it can be changed into another prime (14401351727951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7200675863625 + 7200675863626.
It is an arithmetic number, because the mean of its divisors is an integer number (7200675863626).
Almost surely, 214401351727251 is an apocalyptic number.
14401351727251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14401351727251 is an equidigital number, since it uses as much as digits as its factorization.
14401351727251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 235200, while the sum is 43.
The spelling of 14401351727251 in words is "fourteen trillion, four hundred one billion, three hundred fifty-one million, seven hundred twenty-seven thousand, two hundred fifty-one".
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