Base | Representation |
---|---|
bin | 100000101111111011010101… |
… | …010100001110111010010001 |
3 | 200212222020012212202221120121 |
4 | 200233323111110032322101 |
5 | 122334301003102430100 |
6 | 1230154533351110241 |
7 | 42223616515205302 |
oct | 4057732524167221 |
9 | 625866185687517 |
10 | 144031012155025 |
11 | 419902335319a6 |
12 | 141a2212672381 |
13 | 624a0b24a5b08 |
14 | 277d1d12687a9 |
15 | 119b89cda351a |
hex | 82fed550ee91 |
144031012155025 has 12 divisors (see below), whose sum is σ = 178598617323100. Its totient is φ = 115224705046080.
The previous prime is 144031012155001. The next prime is 144031012155049. The reversal of 144031012155025 is 520551210130441.
It is an interprime number because it is at equal distance from previous prime (144031012155001) and next prime (144031012155049).
It can be written as a sum of positive squares in 6 ways, for example, as 18637801391104 + 125393210763921 = 4317152^2 + 11197911^2 .
It is not a de Polignac number, because 144031012155025 - 217 = 144031012023953 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 37526911 + ... + 41186539.
Almost surely, 2144031012155025 is an apocalyptic number.
It is an amenable number.
144031012155025 is a deficient number, since it is larger than the sum of its proper divisors (34567605168075).
144031012155025 is a wasteful number, since it uses less digits than its factorization.
144031012155025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5233908 (or 5233903 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 144031012155025 its reverse (520551210130441), we get a palindrome (664582222285466).
The spelling of 144031012155025 in words is "one hundred forty-four trillion, thirty-one billion, twelve million, one hundred fifty-five thousand, twenty-five".
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