Base | Representation |
---|---|
bin | 100000101111111100110111… |
… | …100011111010110011001001 |
3 | 200212222101110202022012102112 |
4 | 200233330313203322303021 |
5 | 122334312342032342441 |
6 | 1230155405111312105 |
7 | 42224005411304564 |
oct | 4057746743726311 |
9 | 625871422265375 |
10 | 144032660434121 |
11 | 419909a9989428 |
12 | 141a25b267b635 |
13 | 624a2b5b138a4 |
14 | 277d30a1294db |
15 | 119b94793c4eb |
hex | 82ff378facc9 |
144032660434121 has 2 divisors, whose sum is σ = 144032660434122. Its totient is φ = 144032660434120.
The previous prime is 144032660434111. The next prime is 144032660434177. The reversal of 144032660434121 is 121434066230441.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80924507598025 + 63108152836096 = 8995805^2 + 7944064^2 .
It is an emirp because it is prime and its reverse (121434066230441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 144032660434121 - 222 = 144032656239817 is a prime.
It is not a weakly prime, because it can be changed into another prime (144032660434111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72016330217060 + 72016330217061.
It is an arithmetic number, because the mean of its divisors is an integer number (72016330217061).
Almost surely, 2144032660434121 is an apocalyptic number.
It is an amenable number.
144032660434121 is a deficient number, since it is larger than the sum of its proper divisors (1).
144032660434121 is an equidigital number, since it uses as much as digits as its factorization.
144032660434121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 331776, while the sum is 41.
The spelling of 144032660434121 in words is "one hundred forty-four trillion, thirty-two billion, six hundred sixty million, four hundred thirty-four thousand, one hundred twenty-one".
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