14403401300045 has 4 divisors (see below), whose sum is σ = 17284081560060. Its totient is φ = 11522721040032.

The previous prime is 14403401300009. The next prime is 14403401300149. The reversal of 14403401300045 is 54000310430441.

It is a happy number.

14403401300045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7927704721924 + 6475696578121 = 2815618^2 + 2544739^2 .

It is a cyclic number.

It is not a de Polignac number, because 14403401300045 - 2¹² = 14403401295949 is a prime.

It is a super-2 number, since 2×14403401300045² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14403401299990 and 14403401300017.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1440340130000 + ... + 1440340130009.

It is an arithmetic number, because the mean of its divisors is an integer number (4321020390015).

Almost surely, 2^{14403401300045} is an apocalyptic number.

It is an amenable number.

14403401300045 is a deficient number, since it is larger than the sum of its proper divisors (2880680260015).

14403401300045 is an equidigital number, since it uses as much as digits as its factorization.

14403401300045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2880680260014.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 14403401300045 its reverse (54000310430441), we get a palindrome (68403711730486).

The spelling of 14403401300045 in words is "fourteen trillion, four hundred three billion, four hundred one million, three hundred thousand, forty-five".