Base | Representation |
---|---|
bin | 1101000110011000111011… |
… | …1111011010000110100011 |
3 | 1212222221202101222022121211 |
4 | 3101212032333122012203 |
5 | 3341441203112031042 |
6 | 50344501454330551 |
7 | 3014420165521306 |
oct | 321461677320643 |
9 | 55887671868554 |
10 | 14403424330147 |
11 | 46535045a09a6 |
12 | 17475917b9a57 |
13 | 806310b56438 |
14 | 37b1b5332b3d |
15 | 19e9ed258017 |
hex | d198efda1a3 |
14403424330147 has 2 divisors, whose sum is σ = 14403424330148. Its totient is φ = 14403424330146.
The previous prime is 14403424330091. The next prime is 14403424330153. The reversal of 14403424330147 is 74103342430441.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14403424330147 is a prime.
It is not a weakly prime, because it can be changed into another prime (14403424330177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201712165073 + 7201712165074.
It is an arithmetic number, because the mean of its divisors is an integer number (7201712165074).
Almost surely, 214403424330147 is an apocalyptic number.
14403424330147 is a deficient number, since it is larger than the sum of its proper divisors (1).
14403424330147 is an equidigital number, since it uses as much as digits as its factorization.
14403424330147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 387072, while the sum is 40.
Adding to 14403424330147 its reverse (74103342430441), we get a palindrome (88506766760588).
The spelling of 14403424330147 in words is "fourteen trillion, four hundred three billion, four hundred twenty-four million, three hundred thirty thousand, one hundred forty-seven".
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