Base | Representation |
---|---|
bin | 1101000110011000111011… |
… | …1111110101011100010011 |
3 | 1212222221202102012000020101 |
4 | 3101212032333311130103 |
5 | 3341441203124122011 |
6 | 50344501500553231 |
7 | 3014420166465634 |
oct | 321461677653423 |
9 | 55887672160211 |
10 | 14403424442131 |
11 | 465350466804a |
12 | 1747591852817 |
13 | 806310b953ba |
14 | 37b1b536188b |
15 | 19e9ed27b2c1 |
hex | d198eff5713 |
14403424442131 has 2 divisors, whose sum is σ = 14403424442132. Its totient is φ = 14403424442130.
The previous prime is 14403424442111. The next prime is 14403424442161. The reversal of 14403424442131 is 13124442430441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14403424442131 - 29 = 14403424441619 is a prime.
It is a super-2 number, since 2×144034244421312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14403424442111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7201712221065 + 7201712221066.
It is an arithmetic number, because the mean of its divisors is an integer number (7201712221066).
Almost surely, 214403424442131 is an apocalyptic number.
14403424442131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14403424442131 is an equidigital number, since it uses as much as digits as its factorization.
14403424442131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 147456, while the sum is 37.
Adding to 14403424442131 its reverse (13124442430441), we get a palindrome (27527866872572).
The spelling of 14403424442131 in words is "fourteen trillion, four hundred three billion, four hundred twenty-four million, four hundred forty-two thousand, one hundred thirty-one".
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