Base | Representation |
---|---|
bin | 100000101111111111011101… |
… | …010011101001001010101011 |
3 | 200212222122122112210000010112 |
4 | 200233333131103221022223 |
5 | 122334334040420413301 |
6 | 1230200545044404535 |
7 | 42224134335303404 |
oct | 4057773523511253 |
9 | 625878575700115 |
10 | 144035441185451 |
11 | 419920a660a022 |
12 | 141a30499a674b |
13 | 624a639c6168a |
14 | 277d4d157c9ab |
15 | 119ba5bb239bb |
hex | 82ffdd4e92ab |
144035441185451 has 2 divisors, whose sum is σ = 144035441185452. Its totient is φ = 144035441185450.
The previous prime is 144035441185421. The next prime is 144035441185459. The reversal of 144035441185451 is 154581144530441.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144035441185451 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 144035441185451.
It is not a weakly prime, because it can be changed into another prime (144035441185459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72017720592725 + 72017720592726.
It is an arithmetic number, because the mean of its divisors is an integer number (72017720592726).
Almost surely, 2144035441185451 is an apocalyptic number.
144035441185451 is a deficient number, since it is larger than the sum of its proper divisors (1).
144035441185451 is an equidigital number, since it uses as much as digits as its factorization.
144035441185451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072000, while the sum is 50.
The spelling of 144035441185451 in words is "one hundred forty-four trillion, thirty-five billion, four hundred forty-one million, one hundred eighty-five thousand, four hundred fifty-one".
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