144040004134132 has 12 divisors (see below), whose sum is σ = 252070127884260. Its totient is φ = 72019967595776.

The previous prime is 144040004134123. The next prime is 144040004134141. The reversal of 144040004134132 is 231431400040441.

It is an interprime number because it is at equal distance from previous prime (144040004134123) and next prime (144040004134141).

It can be written as a sum of positive squares in 2 ways, for example, as 87970968352656 + 56069035781476 = 9379284^2 + 7487926^2 .

It is a junction number, because it is equal to n+sod(n) for n = 144040004134094 and 144040004134103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2328918 + ... + 17131954.

It is an arithmetic number, because the mean of its divisors is an integer number (21005843990355).

Almost surely, 2^{144040004134132} is an apocalyptic number.

It is an amenable number.

144040004134132 is a deficient number, since it is larger than the sum of its proper divisors (108030123750128).

144040004134132 is a wasteful number, since it uses less digits than its factorization.

144040004134132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17235650 (or 17235648 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 144040004134132 its reverse (231431400040441), we get a palindrome (375471404174573).

The spelling of 144040004134132 in words is "one hundred forty-four trillion, forty billion, four million, one hundred thirty-four thousand, one hundred thirty-two".