Base | Representation |
---|---|
bin | 10100111101011111001… |
… | …011111010101010011111 |
3 | 12002200221201102110212002 |
4 | 110331133023322222133 |
5 | 142044430204103201 |
6 | 3021414330432515 |
7 | 206031504341642 |
oct | 24753713725237 |
9 | 5080851373762 |
10 | 1440411003551 |
11 | 505969507393 |
12 | 1b31b289273b |
13 | a5aa3b812b0 |
14 | 4da05603a59 |
15 | 27705c8076b |
hex | 14f5f2faa9f |
1440411003551 has 16 divisors (see below), whose sum is σ = 1601142312000. Its totient is φ = 1287173783808.
The previous prime is 1440411003529. The next prime is 1440411003553. The reversal of 1440411003551 is 1553001140441.
It is a cyclic number.
It is not a de Polignac number, because 1440411003551 - 214 = 1440410987167 is a prime.
It is a super-3 number, since 3×14404110035513 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1440411003553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7428446 + ... + 7619883.
It is an arithmetic number, because the mean of its divisors is an integer number (100071394500).
Almost surely, 21440411003551 is an apocalyptic number.
1440411003551 is a deficient number, since it is larger than the sum of its proper divisors (160731308449).
1440411003551 is a wasteful number, since it uses less digits than its factorization.
1440411003551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15048578.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 1440411003551 its reverse (1553001140441), we get a palindrome (2993412143992).
The spelling of 1440411003551 in words is "one trillion, four hundred forty billion, four hundred eleven million, three thousand, five hundred fifty-one".
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