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144041232301 = 467930784619
BaseRepresentation
bin1000011000100110000…
…1101100011110101101
3111202210110222202021121
42012021201230132231
54324444023413201
6150101023300541
713256322162451
oct2061141543655
9452713882247
10144041232301
11560a657a84a
1223abb14a751
1310776bbc105
146d86236661
153b308dd9a1
hex218986c7ad

144041232301 has 4 divisors (see below), whose sum is σ = 144072021600. Its totient is φ = 144010443004.

The previous prime is 144041232299. The next prime is 144041232319. The reversal of 144041232301 is 103232140441.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 144041232301 - 21 = 144041232299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144041232341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15387631 + ... + 15396988.

It is an arithmetic number, because the mean of its divisors is an integer number (36018005400).

Almost surely, 2144041232301 is an apocalyptic number.

It is an amenable number.

144041232301 is a deficient number, since it is larger than the sum of its proper divisors (30789299).

144041232301 is an equidigital number, since it uses as much as digits as its factorization.

144041232301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30789298.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 144041232301 its reverse (103232140441), we get a palindrome (247273372742).

The spelling of 144041232301 in words is "one hundred forty-four billion, forty-one million, two hundred thirty-two thousand, three hundred one".

Divisors: 1 4679 30784619 144041232301